SOLUTION: Please help me solve this equation: {{{ log base 4(x^2+6)=log base 4 (5x) }}}

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Question 749564: Please help me solve this equation: +log+base+4%28x%5E2%2B6%29=log+base+4+%285x%29+
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Recognize that logarithms are to the same base, 4, so the inputs of both logarithms are the same.
If log%284%2Cx%5E2%2B6%29=log%284%2C5x%29,
then+x%5E2%2B6=5x.

x%5E2-5x%2B6=0
%28x-2%29%28x-3%29=0
Either highlight%28x=2%29 Or highlight%28x=3%29.