SOLUTION: For the functions ƒ(x) = log_6(x) and g(x)=log_1/4(x), for what values of x is g(x) > ƒ(x)?

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: For the functions ƒ(x) = log_6(x) and g(x)=log_1/4(x), for what values of x is g(x) > ƒ(x)?      Log On


   

Question 744933: For the functions ƒ(x) = log_6(x) and g(x)=log_1/4(x), for what values of x is g(x) > ƒ(x)?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
For the functions ƒ(x) = log_6(x) and g(x)=log_1/4(x), for what values of x is g(x) > ƒ(x)?
f%281%29=log%286%2C%281%29%29=0
g%281%29=log%281%2F4%2C%281%29%29=0
..
f%280.9%29=log%286%2C%280.9%29%29=-0.0588
g%280.9%29=log%281%2F4%2C%280.9%29%29=0.0760
..
At x=1, g(x)=f(x)
At x<1, g(x)>f(x)
Between (0 and 1), f becomes more negative as x becomes more negative; whereas, g becomes more positive as x becomes more negative.