SOLUTION: hi.please help me with this problem..i can't find in any of my information on this hand out about antilog.. the question is antilog 2.1784=_______ i figured 150.8 but i am re

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: hi.please help me with this problem..i can't find in any of my information on this hand out about antilog.. the question is antilog 2.1784=_______ i figured 150.8 but i am re      Log On


   

Question 74481: hi.please help me with this problem..i can't find in any of my information on this hand out about antilog..
the question is
antilog 2.1784=_______
i figured 150.8 but i am really not sure how i got that..thanks for any help.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The antilog is the same as saying 10%5Ex (it undoes the log). So just plug in x=2.7184
10%5E%282.7184%29=150.7995 which if rounded would be 150.8 so you did that right.