SOLUTION: log base 4 (8x-9)-log base 4 (x+1)=1

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Question 744302: log base 4 (8x-9)-log base 4 (x+1)=1
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
log%284%2C%288x-9%29%29-+log%284%2C%28x%2B1%29%29 = 1
we write this over a single log, subtraction means divide:
log%284%2C%28%288x-9%29%2F%28x%2B1%29%29%29 = 1
The exponent equiv
%28%288x-9%29%2F%28x%2B1%29%29 = 4%5E1
or just
%28%288x-9%29%2F%28x%2B1%29%29 = 4
multiply both sides by (x+1)
8x - 9 = 4(x + 1)
8x - 9 = 4x + 4
8x - 4x = 4 + 9
4x = 13
x = 13/4
x = 3.25