SOLUTION: 6. Given log(3) = 0.47712 , find a approximation for each logarithm
a) log(30)
b) log(3000)
c) log(.3)
d) log(.003)
e) log(9)
f) log(81)
g) log(√3)
Can you please h
Algebra.Com
Question 739791: 6. Given log(3) = 0.47712 , find a approximation for each logarithm
a) log(30)
b) log(3000)
c) log(.3)
d) log(.003)
e) log(9)
f) log(81)
g) log(√3)
Can you please help me out? Thanks so much in advance:)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
6. Given log(3) = 0.47712 , find a approximation for each logarithm
a) log(30)=log(10*3)=log(10)+log(3)=1+.47712=1.47712
b) log(3000)=log(1000*3)=log(1000)+log(3)=3+.47712=3.47712
c) log(.3)=log(10^(-1)*3)=-1+log(3)=-1+.47712=-0.52288
d) log(.003)=log(10^(-3)*3)=-3+log(3)=-3+.47712=-2.52288
e) log(9)=log(3^2)=2log(3)=2*.47712=0.95424
f) log(81)=log(3^3)=3log(3)=3*.47712=1.43136
g) log(√3)=(1/2)log(3)=1/2*.47712=0.23856
note: log of base raised to an exponent=exponent; e.g. log 10^3=3
RELATED QUESTIONS
8. Given log(70) = 1.8451 , find a approximation for each logarithm
a) log(7)
b)... (answered by lwsshak3)
Given log(base 3)10= 2.0959 find an approximation for each logarithm
a) log(base 3)1000
(answered by nerdybill)
Given log(base 3)10= 2.0959 find an approximation for each logarithm
a) log(base 3)1000
(answered by lwsshak3)
Evaluate each logarithm
a. log(16)1
b. log (e)e4
c. log(10)0.01
d. log(3)27
e.... (answered by lwsshak3)
Evaluate each logarithm
a. log[16]1
b. log[e]e4
c. log[10]0.01
d. log[3]27
e.... (answered by lwsshak3)
Write as a single logarithm
a) 2 log 5 log b
b) 3 log x + 1/2 log y
c) 2 log m + log n (answered by lwsshak3)
Use your calculator to evaluate each expression
a) log(base 2)3000
b) log(base 2)300... (answered by stanbon)
Write as a single logarithm: 2 log A-3 log B+4 log... (answered by Alan3354)
[log 3]/[log 81] (answered by Edwin McCravy)