log10x-log(x-3)=log2
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is NOT a solution to this logarithmic equation, as stated by the other person, since it's EXTRANEOUS!
log (10x) - log (x - 3) = log (2)
x - 3 is the smaller of the 2 variable-arguments, and so, MUST be > 0. This gives us: x - 3 > 0 ====> x > 3
We then have: log (10x) - log (x - 3) = log (2), with x > 3
While the solution to this equation is x = , this value is NOT > 3, and so, is INVALID/UNACCEPTABLE.
As a result, NO SOLUTION exists for this equation!.
