SOLUTION: How do I write this in logarithimic form? 16^-1/2 = 1/4 Can you show me how to get there?

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Question 729746: How do I write this in logarithimic form? 16^-1/2 = 1/4
Can you show me how to get there?
Found 2 solutions by MathLover1, lwsshak3:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
16%5E%28-1%2F2%29+=+1%2F4

To do these ask yourself three questions.
1. What is the base? Answer: 16
2. What is the exponent? Answer: -%281%2F2%29
3. What is the result? Answer: 1%2F4
Now remember this: log means exponent.
So you should write:
log%28base%2Cresult%29+=+exponent.....put in the exponent -%281%2F2%29
log%28base%2Cresult%29+=+-%281%2F2%29....then you should put in the base:16
log%2816%2Cresult%29=-%281%2F2%29...then you should put in the result:1%2F4
log%2816%2C%281%2F4%29%29+=+-%281%2F2%29

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do I write this in logarithimic form? 16^-1/2 = 1/4
Given equation is written in exponential form:base(16) raised to log of the number(-1/2)=number(1/4)
In logarithmic form: log16(1/4)=-1/2
This reads: log of (1/4) base 16=-1/2