SOLUTION: if a={{{1003*(2006^2007+1/2006^2007)}}} b={{{1003*(2006^2007-1/2006^2007)}}} compute {{{(a^2-b^2)/2006}}}
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-> SOLUTION: if a={{{1003*(2006^2007+1/2006^2007)}}} b={{{1003*(2006^2007-1/2006^2007)}}} compute {{{(a^2-b^2)/2006}}}
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Question 72901
:
if a=
b=
compute
Answer by
rahman(247)
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=
=========================================
a+b=
+
=
=
=
=
============================
a-b=
-
=
=
=
=
============================
=
=
=
=
=2006