Question 724595: y=1/5 log(base3)(9x-36)^(15) - 13
Apply the laws of logarithms to change the form of the equation. Graph the function by first stating the basic function and then describe each transformation applied in order. Specifically describe what happens to the domain, range, asymptotes, x-intercept, and vertical stretch or compression.
I have a problem with this. What i have tried already:
y= -7 -3log(base3)(x-4)
Found 2 solutions by stanbon, jsmallt9: Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! y=1/5 log(base3)(9x-36)^(15) - 13
Apply the laws of logarithms to change the form of the equation.
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y = log3(9x-36)^3 - 13
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Graph the function by first stating the basic function and then describe each transformation applied in order. Specifically describe what happens to the domain, range, asymptotes, x-intercept, and vertical stretch or compression.
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Before Transformation:
y = log3(x)
Domain: x > 0
Range: All Real Numbers
Asymp: x = 0
x-int: log3(x) = 0
x = 3*0 = 1
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stretch or compress: none
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After Transformation::
Domain: x > 4
Range: All Real Numbers
Asymp: x = 4
x-int: Let y = 0 ; solve for "x"
(9x-36)^3 = 3^13
9x-36 = 3^(13/3) = 116.82
9x = 152.82
x = 16.98
Stretch: Around 30
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cheers,
Stan H.
Answer by jsmallt9(3758) (Show Source):
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