SOLUTION: How would you solve: log (base 3)of 2+ log (base 3)of 7= log (base 3)of x or (1/4)log 15+ (1/2)log 49= logx Either problem would be great! I really appreciate it, than

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: How would you solve: log (base 3)of 2+ log (base 3)of 7= log (base 3)of x or (1/4)log 15+ (1/2)log 49= logx Either problem would be great! I really appreciate it, than      Log On


   



Question 701641: How would you solve:
log (base 3)of 2+ log (base 3)of 7= log (base 3)of x
or
(1/4)log 15+ (1/2)log 49= logx
Either problem would be great! I really appreciate it, thanks so much. I really looked everywhere and tried numerous times, hopefully I can finally get the answer! Thanks! :)

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
log (base 3)of 2+ log (base 3)of 7= log (base 3)of x
log%283%2C2%29+%2B+log%283%2C7%29+=+log%283%2Cx%29
log%283%2C2%2A7%29+=+log%283%2Cx%29
log%283%2C14%29+=+log%283%2Cx%29
14+=+x
or
(1/4)log 15+ (1/2)log 49= logx
%281%2F4%29log%2810%29+%2B+%281%2F2%29log%2849%29+=+log%28x%29
log%2810%5E%281%2F4%29%29+%2B+log%2849%5E%281%2F2%29%29+=+log%28x%29
log%2810%5E%281%2F4%29%29+%2B+log%287%29+=+log%28x%29
log%287%2A10%5E%281%2F4%29%29+=+log%28x%29
7%2A10%5E%281%2F4%29+=+x
12.45+=+x