SOLUTION: log base 1/5 ((x^2)+x) - log base 1/5 ((x^2)-x) = -2 x=?

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Question 694528: log base 1/5 ((x^2)+x) - log base 1/5 ((x^2)-x) = -2
x=?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log base 1/5 ((x^2)+x) - log base 1/5 ((x^2)-x) = -2
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log1/5[(x^2+x)/(x^2-x)] = -2
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(x^2+x)/(x^2-x) = (1/5)^-2
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(x+1)/(x-1) = 25
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x+1 = 25x-25
24x = 26
x = 13/12
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Cheers,
Stan H.
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