SOLUTION: log(x+3)-log(x-3)=log(x-1) how do I solve?

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Question 691417: log(x+3)-log(x-3)=log(x-1) how do I solve?
Found 2 solutions by stanbon, mouk:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log(x+3)-log(x-3)=log(x-1)
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log[(x+3)/(x-3)] = log(x-1)
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Take the anti-log of both sides to get:
(x+3)/(x-3) = x-1
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Cross-multiply:
x+3 = x^2-4x+3
----
x^2 -5x = 0
Factor:
x(x-5) = 0
x = 0 or x = 5
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Cheers,
Stan H.
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Answer by mouk(232) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28x%2B3%29-log%28x-3%29=log%28x-1%29+
+log%28%28x%2B3%29%2F%28x-3%29%29=log%28x-1%29+ (using +log%28a%29-log%28b%29+=+log%28a%2Fb%29+)
+%28x%2B3%29%2F%28x-3%29=x-1+ (taking anti-logarithms)
+x%2B3+=+%28x-3%29%28x-1%29+
+x%2B3+=+x%5E2-4x%2B3+
+x%5E2-4x%2B3+=+x%2B3+
+x%5E2-5x=0+
+x%28x-5%29=0+
so +x=0+ or +x=5+
But original question had +log%28x-3%29+ so +x-3+%3E0+ or +x%3E3+
so, solution is +x=5+