Question 687535: To solve the logorithmic log5x^2=log5(5x+14)
(not sure how to write the 5 properly, but its supposed to be small text, base 5)
I get -2 and 7 as my answer, but I'm not 100% confident in my answer selection as this gives me the options of -2 only, 7 only,-2 and 7, and a no solution.
Answer by MathTherapy(10557)   (Show Source):
You can put this solution on YOUR website!
To solve the logorithmic log5x^2=log5(5x+14)
(not sure how to write the 5 properly, but its supposed to be small text, base 5)
I get 7 and - 2 as my answer, but I'm not 100% confident in my answer selection as this gives me the options of -2 only, 7 only,-2 and 7, and a no solution.
You need to learn how to check your answers!!
All you need to do is PLUG in or substitute each answer value into the original equation to determine if each makes the equation TRUE. The  solution is checked below:
Is the above TRUE, or false? It clearly is TRUE, so we know, for sure that is indeed one of the solutions to the equation. Now all you have to do is test  by plugging that value into the original equation to determine if it makes the equation TRUE. If so, then both are solutions. Be certain that a log of a NEGATIVE NUMBER doesn't arise. If so, then that's clearly NOT a solution of the set.
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