SOLUTION: Find all the real number roots of the equation. log2(x+7)-log2(x-3)=3

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Question 685595: Find all the real number roots of the equation.
log2(x+7)-log2(x-3)=3
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find all the real number roots of the equation.
log2(x+7)-log2(x-3)=3
log2[(x+7)/(x-3)]=3
convert to exponential form
(x+7)/(x-3)=2^3=8
x+7=8x-24
7x=31
x=31/7=4.4286..