SOLUTION: Can you help me solve. I'm having problems using the laws. thanks in advance. Log2t^3-Logt = Log16+Logt

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Question 684196: Can you help me solve. I'm having problems using the laws. thanks in advance.
Log2t^3-Logt = Log16+Logt
Found 2 solutions by lwsshak3, MathTherapy:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Log2t^3-Logt = Log16+Logt
log[2t^3/t]=log[16/t]
2t^3/t=16/t
2t^3=16
t^3=8
t=2

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

Can you help me solve. I'm having problems using the laws. thanks in advance.
Log2t^3-Logt = Log16+Logt

log+%282t%5E3%29+-+log+t+=+log+16+%2B+log+t

log+%28%282t%5E3%29%2Ft%29+=+log+16t

%282t%5E3%29%2Ft+=+16t

2t%5E3+=+16t%5E2 ------ Cross-multiplying

2t%5E3+-+16t%5E2+=+0

2t%5E2%28t+-+8%29+=+0

highlight_green%28t+=+8%29 OR t = 0 (ignore as log of a number CANNOT = 0)

You can do the check!!

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