SOLUTION: log_2(x+5) - log_2(x) = 4 and 2^(3x-2)= 3^(2x-1)

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Question 683329: log_2(x+5) - log_2(x) = 4
and
2^(3x-2)= 3^(2x-1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log_2(x+5) - log_2(x) = 4
I think you mean base 2
log%282%2C%28x%2B5%29%29+-+log%282%2Cx%29+=+4
log%282%2C%28x%2B5%29%2Fx%29+=+4
x%2B5%29%2Fx+=+2%5E4+=+16
x+5 = 16x
15x = 5
x = 1/3
===========
and
2^(3x-2)= 3^(2x-1)
(3x-2)*log(2) = (2x-1)*log(3)
etc