SOLUTION: find y' if e^(x^8*y) = x + y. I attempted but got lost?

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Question 665734: find y' if e^(x^8*y) = x + y.
I attempted but got lost?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
find y' if e^(x^8*y) = x + y.
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Differentiate implicitly
dx + dy = e^(x^8*y)*(8x^7dx*y + x^8dy)
dy = e^(x^8*y)*8x^7ydx + e^(x^8y)*x^8dy - dx
dy - e^(x^8y)*xdy = e^(x^8*y)*8x^7y - dx
dy*(1 - e^(x^8y)*x) = dx*(e^(x^8*y)*8x^7y - 1)
dy%2Fdx+=+%28e%5E%28x%5E8%2Ay%29%2A8x%5E7y+-+1%29%2F%281+-+e%5E%28x%5E8y%29%2Ax%29