SOLUTION: Hi,I really appreciate you trying to help me!! I have this question that I do not really know how to answer, so I hope you can help me, please!! {{{ log (y,1) }}} {{{ log (y,x)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi,I really appreciate you trying to help me!! I have this question that I do not really know how to answer, so I hope you can help me, please!! {{{ log (y,1) }}} {{{ log (y,x)      Log On


   



Question 6634: Hi,I really appreciate you trying to help me!! I have this question that I do not really know how to answer, so I hope you can help me, please!!
+log+%28y%2C1%29+ +log+%28y%2Cx%29+
where 1 is less than x and less than y, is the answer positive or negative???
I think that I am supposed to sub in a number less than 1 in both x and y and see what the sign of the final answer is????? I hope you can help me and thank you!!!!

Answer by khwang(438) About Me  (Show Source):
You can put this solution on YOUR website!
Somehow stange since
+log+%28y%2C1%29+ is always = 0
Also, use math notation instead of
"where 1 is less than x and less than y"
means 1 < x < y or (1 < x and 1 < y) ???
Note if 1 < x < y then +log+%28y%2Cx%29+ < 1
Kenny