SOLUTION: evaluate log 2(y -3) + log 4 base 2 =2

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Question 659802: evaluate log 2(y -3) + log 4 base 2 =2
Answer by lwsshak3(11628) About Me  (Show Source):
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evaluate log 2(y -3) + log 4 base 2 =2
log2(y-3) + log2(4) =2
log2[(y-3)*4]=log2(4)
4(y-3)=4
y-3=1
y=4