SOLUTION: Solve for L. V = K log base e (1+ L/b)
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Question 655041
:
Solve for L. V = K log base e (1+ L/b)
Answer by
stanbon(75887)
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Solve for L. V = K log base e (1+ L/b)
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ln(1+L/b) = V/K
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1 + (L/b) = e^(V/R)
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L/b = e^(V/R) - 1
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L = b[e^(V/R) - 1]
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Cheers,
Stan H.
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