SOLUTION: logbase3(logbaseX(logbase416))=-1
I thought perhaps I must simply just add (which multiplies) so i took it out of the brackets.
I was getting
logbase3 +logbaseX +logbase4 4^2
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-> SOLUTION: logbase3(logbaseX(logbase416))=-1
I thought perhaps I must simply just add (which multiplies) so i took it out of the brackets.
I was getting
logbase3 +logbaseX +logbase4 4^2
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Question 633478: logbase3(logbaseX(logbase416))=-1
I thought perhaps I must simply just add (which multiplies) so i took it out of the brackets.
I was getting
logbase3 +logbaseX +logbase4 4^2 <-fours cancel out right?
Then I got logbase3 +logbase X +2=-1
then log base3 +log base X=-3
Then I am lost.
Please help? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! logbase3(logbaseX(logbase4(16))=-1
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log3(logx(log4(16)) = -1
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Work from right to left:
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= log3(logx(2)) = -1
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logx(2) = 3^-1
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logx(2) = 1/3
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2 = x^(1/3)
x = 2^3 = 8
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Cheers,
Stan H.
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