SOLUTION: Solve log(x) + log(x-3)=1
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Question 62959
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Solve log(x) + log(x-3)=1
Answer by
stanbon(75887)
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Solve log(x) + log(x-3)=1
log[x(x-3)]=1
x^2-3x=10^1
x^2-3x-10=0
(x-5)(x+2)=0
x=5 or x=-2
x-2 is an extraneous solution
because log(-2) does not exist.
Final Solution: x=5
Cheers,
Stan H.