SOLUTION: how to write this as single logarithm. 1.log7 + log3 = x 2.log9 + log8 - log6
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Question 625064
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how to write this as single logarithm.
1.log7 + log3 = x
2.log9 + log8 - log6
Answer by
lwsshak3(11628)
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how to write this as single logarithm.
1.log7 + log3 = x
log[7*3]=x
log[21]=x
..
2.log9 + log8 - log6
=log[(9*8)/6]
=log[12]