SOLUTION: how do you solve log base5(x^2+7)=2/3log base5(64) Can you please show work

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Question 624649: how do you solve log base5(x^2+7)=2/3log base5(64)
Can you please show work
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
how do you solve:
log base5(x^2+7)=2/3log base5(64)
log5(x^2+7)=2/3log5(64)
log5(x^2+7)=log5(64^(2/3))
64^(2/3)=16
log5(x^2+7)=log5(16)
x^2+7=16
x^2=9
x=±3