You can put this solution on YOUR website! e^x = 2^(x+1)
ln(e^x)=ln(2^(x+1))
xln(e)=(x+1)ln(2)
x(1)=(x+1)ln(2)
x=xln(2)+ln(2)
x-xln(2)=ln(2)
x(1-ln(2))=ln(2)
x(1-ln(2))/(1-ln(2))=ln(2)/(1-ln(2))
x=ln(2)/(1-ln(2))
x=2.258891353 approximatlely.
Happy Calculating!!!