SOLUTION: f(x)=log(base 5)x; Solve and find A) x=1 B) x=125 A) f(1)= log(base 5)(1) = 5log(base5)(1) = 1 B) f(125)= log(base 5)(125) = 5^x=125

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: f(x)=log(base 5)x; Solve and find A) x=1 B) x=125 A) f(1)= log(base 5)(1) = 5log(base5)(1) = 1 B) f(125)= log(base 5)(125) = 5^x=125       Log On


   

Question 601462: f(x)=log(base 5)x;
Solve and find
A) x=1
B) x=125

A) f(1)= log(base 5)(1)
= 5log(base5)(1)
= 1
B) f(125)= log(base 5)(125)
= 5^x=125
= log5^x= log125
= xlog5=log125
= xlog5/log5= log125/log5
= 3
Were these two problems done correctly?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=log(base 5)x;
Solve and find
A) x=1
f(1) = log5(1) = log(1)/log(5) = 0/5 = 0
f(1) = 0
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B) x=125
f(125) = log5(125) = log(125)/log(5) = 3
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Cheers,
Stan H.
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