SOLUTION: Solve: for x and state anything that needs to be rejected, solve using logs 5^(x^2-3x )= 625 THANKS SOO MUCH!

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Question 597972: Solve: for x and state anything that needs to be rejected, solve using logs
5^(x^2-3x )= 625




THANKS SOO MUCH!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+5%5E%28x%5E2-3x+%29=+625+
Note that +625+=+5%5E4+
Let +y+=+x%5E2+-+3x+
+5%5Ey+=+5%5E4+
Take the log to base 5 of both sides
+log%28+5%2C+5%5Ey+%29+=+y+
+log%28+5%2C+5%5E4+%29+=+4+
+y+=+4+
+x%5E2+-+3x+=+4+
+x%5E2+-3x+-+4+=+0+
+%28+x+-+4+%29%2A%28+x+%2B+1+%29+=+0+
+x+=+4+
+x+=+-1+
Both these answers work in original equation