SOLUTION: How do you solve log4(9z+5)-log4(2z+2)=1? I've went over all of my lessons but I still don't understand it. Please show all work so I understand how to do it.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: How do you solve log4(9z+5)-log4(2z+2)=1? I've went over all of my lessons but I still don't understand it. Please show all work so I understand how to do it.      Log On


   

Question 581399: How do you solve log4(9z+5)-log4(2z+2)=1? I've went over all of my lessons but I still don't understand it. Please show all work so I understand how to do it.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve log4(9z+5)-log4(2z+2)=1? I've went over all of my lessons but I still don't understand it. Please show all work so I understand how to do it.
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log4(9z+5)-log4(2z+2)=1
use division rule for logs
log4[(9z+5)/2z+2)]=1
convert to exponential form: base(4) raised to log of the number(1)=number(9z+5)/2z+2)
4^1=(9z+5)/2z+2)
4=(9z+5)/2z+2)
9z+5=8z+8
z=3