SOLUTION: I have tried but i cannot solve this equation, I would appreciate some help, pls log(x+1)^2 + log(x+9)^2 = 2log9

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Question 561140: I have tried but i cannot solve this equation, I would appreciate some help, pls
log(x+1)^2 + log(x+9)^2 = 2log9

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I have tried but i cannot solve this equation, I would appreciate some help, pls
log(x+1)^2 + log(x+9)^2 = 2log9
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Assuming it's log( (x+1)^2) and not the log^2:
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2log(x+1) + 2log(x+9) = 2log9
log(x+1) + log(x+9) = log(9)
log((x+1)*(x+9) = log(9)
x%5E2+%2B+10x+%2B+9+=+9
x = 0, x = -10
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-10 won't work, so ignore it.
--> x = 0