SOLUTION: solve for X: log4 (x^2+3x)=1

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Question 531768: solve for X: log4 (x^2+3x)=1
Answer by lwsshak3(11628) About Me  (Show Source):
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solve for X: log4 (x^2+3x)=1
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log4 (x^2+3x)=1
Convert to exponential form: base(4) raised to log of number(1)=number(x^2+3x)
4^1=(x^2+3x)
x^2+3x-4=0
(x+4)(x-1)=0
x=-4
or
x=1