SOLUTION: Write 5(1.06^2x+1)=11 as a logarithmic equation then solve

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Question 499032: Write 5(1.06^2x+1)=11 as a logarithmic equation then solve
Answer by lwsshak3(11628) About Me  (Show Source):
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Write 5(1.06^2x+1)=11 as a logarithmic equation then solve
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5(1.06^2x+1)=11
=5*1.06^2x+5=11
=5*1.06^2x=11-5=6
=1.06^2x=6/5
Take log of both sides
2xlog(1.06)=log(6/5)
2x=log(6/5)/log(1.06)=3.129
x=1.5645
Check:
5(1.06^2x+1)=5*(1.06^(2*1.5645)+1)=5*2.2=11