SOLUTION: logx=(1/2log173-1/2log32)divided by(log5-log32.find x.
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Question 481172
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logx=(1/2log173-1/2log32)divided by(log5-log32.find x.
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lwsshak3(11628)
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logx=(1/2log173-1/2log32)divided by(log5-log32.find x.
**
logx=log[(173)^1/2/(32)^1/2]/log[5/32]
logx=log[√173/√32]/log[5/32]
logx=log(2.3251)/log(.1563)
logx=.3664/-.8060=-.4546
x=10^-.4546=.3511