SOLUTION: (log2x+logx)/(log2x-logx)=3

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: (log2x+logx)/(log2x-logx)=3      Log On


   

Question 471131: (log2x+logx)/(log2x-logx)=3
Found 2 solutions by Alan3354, nerdybill:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(log2x+logx)/(log2x-logx)=3
log%282x%5E2%29%2Flog%282%29+=+3
log%282x%5E2%29+=+3log%282%29+=+log%282%5E3%29+=+log%288%29
2x%5E2+=+8
x = 2
-----
x = -2 is rejected due to the logs

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!

(log2x+logx)/(log2x-logx)=3
(log2x+logx)-(log2x-logx)=3
log2x+logx-log2x+logx=3
logx+logx=3
2logx=3
logx=3/2
x = 10^(3/2)
x = 31.623