SOLUTION: log2(x) + log2(8) = log2(64 − x) + 3 Solve for x

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Question 470124: log2(x) + log2(8) = log2(64 − x) + 3
Solve for x
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log2(x) + log2(8) = log2(64 − x) + 3
Solve for x
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log2(x) + 3 = log2(64-x) = 3
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log2(x) = log2(64-x)
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x = 64-x
2x = 64
x = 32
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Cheers,
Stan H.
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