Question 460058: I was given an equation and the book explained for to solve it using a graphing calculator but I would like to understand how it's done algebraically.
e^(0.5x)-7.3= 2.08x + 6.2
This is how far I got before I drew a blank. Any help would be awesome.
e^(0.5x)= 2.08x+13.5
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! There's no way to solve this equation algebraically because the variable we're solving for is located in the exponent on the left side and it's not located in the exponent on the right side. Basically, if the variable is located in the exponent, then EVERY copy of that variable must also be an exponent as well. To solve this, we would use the lambert W function, but that's beyond the scope of most courses. So you're going to have to settle to find the approximate solution. In this case, your book is having you use your graphing calculator to find these approximate solutions.
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