Question 454900: Solve for x:
log base 4 of(x^2+3x) - log base 4 of(x+5)=1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! log base 4 of(x^2+3x) - log base 4 of(x+5) = 1
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log4[(x^2+3x)/(x+5)] = 1
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(x^2+3x)/(x+5) = 4
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x^2+3x = 4x+20
x^2-x-20 = 0
Factor:
(x-5)(x+4) = 0
x = 5 or x = -4
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Cheers,
Stan H.
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