Question 449580: evaluate
a^log{a,w}=x
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! evaluate
a^log{a,w}=x
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a^[loga(w)] = x
---
base = a
exponent or log = loga(w)
result = x
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Log Form:
log[a^(loga(w))] = logx
---
loga(w)*log(a) = log(x)
------
loga(w) = log(x)/log(a)
---
loga(w) = loga(x)
x = w
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Cheers,
Stan H.
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