Question 435229: what is the unknown of log5 v + log1/3 9 + log 9 81 = -4
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! what is the unknown of log5 (v) + log1/3 (9) + log 9 (81) = -4
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Note:
Solve:
(1/3)^x=9
3^-x = 3^2
x = -2
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Solve:
9^x = 81
8^x = 9^2
x = 2
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Put those values where they belong and solve for "v":
log5(v) + (-2) + (2) = -4
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log5(v) = -4
v = 5^(-4)
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v = 1/625
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Cheers,
Stan H.
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