SOLUTION: {{{log(4,4^(-.38))}}} I know the answer is -.38, but why?

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Question 433844: log%284%2C4%5E%28-.38%29%29
I know the answer is -.38, but why?

Found 4 solutions by psbhowmick, shree840, tinbar, Edwin McCravy:
Answer by psbhowmick(878) About Me  (Show Source):
Answer by shree840(260) About Me  (Show Source):
You can put this solution on YOUR website!
Log(4)(4^-.38)
= -.38*Log(4)4
=-.38 ANS

Answer by tinbar(133) About Me  (Show Source):
You can put this solution on YOUR website!
in general if you have a statement: log[b](b^x), where [b] is the base of the log. This statement is equivalent to x*log[b](b), now the second part, log[b](b) is asking b^? = b. obviously ?=1 meaning b^1=b. so the second part simplifies to 1, and so log[b](b^x) = x*log[b](b) = x*1 = x.
In your particular problem x = -.38 and b = 4

Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!
log%284%2C4%5E%28-.38%29%29

I think this explanation might be a little better:

Once you understand what log%28B%2CA%29 actually means, you will
find this trivial.
 
log%28B%2CA%29

is defined as the answer to the question  

"To what power (exponent) must B be raised to give A?"

Examples
 
log%285%2C25%29

is defined as the answer to the question  

"To what power (exponent) must 5 be raised to give 25?"

The answer to that is 2, because if 5 is raised to the power of 2,
that will 25.

So we write log%285%2C25%29=2


-----

log%283%2C81%29

is defined as the answer to the question  

"To what power (exponent) must 3 be raised to give 81?"

The answer to that is 4, because if 3 is raised to the power of 4,
that will 81.

So we write log%283%2C8%29=4

------------------------------------

Now your problem:

log%284%2C4%5E%28-.38%29%29

is defined as the answer to the question  

"To what exponent must 4 be raised to give 4-.38?"

The answer to that is -.38, because if 4 is raised to the power of -.38,
that will give 4-.38"

So we write log%284%2C4%5E%28-.38%29%29=-.38

----------------

In general, we write log%28B%2CB%5EC%29=C because the power to which B must
be raised to give BC is obviously C.
 
Edwin