SOLUTION: combine the logarithmic expressions, then solve for x. log3(8x-13)-log3(12x+21)=-1

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Question 429398: combine the logarithmic expressions, then solve for x.
log3(8x-13)-log3(12x+21)=-1

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
log%283%2C+%288x-13%29%29-log%283%2C+%2812x%2B21%29%29+=+-1
To combine these logarithms we'll use one of the properties of logarithms:
log%28a%2C+%28p%29%29+-+log%28a%2C+%28q%29%29+=+log%28a%2C+%28p%2Fq%29%29
Using this property on the left side of your equation we get:
log%283%2C+%28%288x-13%29%2F%2812x%2B21%29%29%29+=+-1
Now that the equation is in the form of
log(expression) = other-expression
we can solve it by rewriting the equation in exponential form. In general log%28a%2C+%28p%29%29+=+1 is equivalent to p+=+a%5Eq. Using this pattern on your equation we get:
%288x-13%29%2F%2812x%2B21%29+=+3%5E%28-1%29
Since 3%5E%28-1%29+=+1%2F3 this is:
%288x-13%29%2F%2812x%2B21%29+=+1%2F3
This equation we can solve. Since it is a proportion (A "fraction equals a fraction" equation is called a proportion.) we can cross-multiply:
(8x-13)3 = (12x+21)1
Simplifying each side we get:
24x-39 = 12x + 21
Subtracting 12x from each side:
12x + 39 = 21
Subtracting 39 from each side:
12x = -18
Dividing both sides by 12:
x+=+-18%2F12
which reduces to
x+=+-3%2F2

When solving logarithmic equations you must check your answer(s). You must ensire that your answer(s) make all arguments to logarithms positive. Any "solution" that make an argument zero or negative must be rejected.

Use the original equation to check:
log%283%2C+%288x-13%29%29-log%283%2C+%2812x%2B21%29%29+=+-1
Checking x = -3/2:
log%283%2C+%288%28-3%2F2%29-13%29%29-log%283%2C+%2812%28-3%2F2%29%2B21%29%29+=+-1
Simplifying:
log%283%2C+%28-12%29-13%29%29-log%283%2C+%28-18%29%2B21%29%29+=+-1
log%283%2C+%28-25%29%29-log%283%2C+%283%29%29+=+-1
As we can see, the first argument if negative. So we must reject this "solution". (Arguments to logarithms must be positive.) And since this was the only solution we found, there is no solution to your equation.