Question 395535: I need help solving for x..
16^(3logsub2base4)=(1/2)^(logsub5basex)
and also in..
20^(3x-4)=4^x
thank you!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I need help solving for x..
16^(3logsub2base4)=(1/2)^(logsub5basex)
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(2^4)^(3log2(4)) = (2^-1)^(log5(x))
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= 2^(12log2(4)) = 2^(-log5(x))
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12log2(4) = -log5(x)
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12*2 = -log5(x)
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log5(x^-1)= 24
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x^-1 = 5^24
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x = 1/(5^24)
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x = 1.678x10^-17
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Cheers,
Stan H.
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20^(3x-4)=4^x
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(3x-4)log(20) = xlog(4)
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[(3x-4)/x] = log(4)/log(20)
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(3x-4)/x] = 0.4628
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3x-4 = 0.4628x
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2.5372x = 4
x = 1.5765..
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Cheers,
Stan H.
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