SOLUTION: Solve e^2x -6e^x +5=0 algebraically. Find exact solutions, expressing the answer in terms of natural logarithms.

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Question 384326: Solve e^2x -6e^x +5=0 algebraically. Find exact solutions, expressing the answer in terms of natural logarithms.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The equation can be treated as a quadratic equation in e%5Ex. That said, the equation factors as follows:
%28e%5Ex+-+1%29%28e%5Ex+-+5%29+=+0.
Hence either e%5Ex+=+1 or e%5Ex+=+5.
These give the values x = 0 or x = ln5.