SOLUTION: How do you solve for X in this equation?: {{{ 2ln4x=15 }}}

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Question 381355: How do you solve for X in this equation?: +2ln4x=15+
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
2ln(4x)=15
With a variable in the argument of a logarithm, you usually start by transforming the equation into one of the following forms:
log(expression) = other-expression
or
log(expression) = log(other-expression)

All we have to do to your equation to reach the first form is to divide by 2:
ln%284x%29+=+15%2F2
With the first form, the next step is to rewrite the equation in exponential form. In general log%28a%2C+%28p%29%29+=+q is equivalent to p+=+a%5Eq. Using this on your equation we get:
4x+=+e%5E%2815%2F2%29 (Since e is the base of ln.)
And last of all, we multiply by 1/4. (Dividing by 4 works, too.)
x+=+%281%2F4%29e%5E%2815%2F2%29
This is an exact expression for the solution to your equation.