Question 368023: solve for 'x' :
4logx-logx^3 +log2 = log(6-x)
Answer by robertb(5830)   (Show Source):
You can put this solution on YOUR website! log(x^4) - log(x^3)+log2 = log(6-x).
log(x^4/x^3)+log2 = log(6-x),
logx+log2 = log(6-x),
log(2x) = log(6-x),
2x = 6-x, since log is a 1-to-1 function. Hence
3x = 6,
x = 2. This satisfies the original equation, and thus is the final answer.
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