SOLUTION: log4(x-1)+log2(3x+4) is it a trick because it is not equal to anything? also we cannot use calculators thanks,GodBless

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Question 367587: log4(x-1)+log2(3x+4)

is it a trick because it is not equal to anything?
also we cannot use calculators
thanks,GodBless
Answer by Jk22(389) About Me  (Show Source):
You can put this solution on YOUR website!
log4(x-1)+log2(3x+4) = log4(x-1)+log(3x+4)/log(2)

= log4(x-1)+log4(3x+4)*log(4)/log(2)

= log4(x-1)+2log4(3x+4)

= log4((x-1)(3x+4)^2)