SOLUTION: if log(base3)x=7, evaluate the following. log(base3)9x

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Question 315119: if log(base3)x=7, evaluate the following. log(base3)9x
Found 2 solutions by malaydassharma, MathTherapy:
Answer by malaydassharma(59) About Me  (Show Source):
You can put this solution on YOUR website!
if log(base3)x = 7 , then
x=3%5E7

hence, log(base3)9x
=log%28base3%29+9X3%5E7
=log%28base3%29+3%5E9
=9+log%28base3%29+3+=+9

Answer by MathTherapy(10699) About Me  (Show Source):
You can put this solution on YOUR website!
 if log(base3)x=7, evaluate the following. log(base3)9x

   log+%283%2C+%28x%29%29+=+7
  log%283%2C+%289x%29%29+=+log+%283%2C+%289%29%29+%2B+log+%283%2C+%28x%29%29 ---- Applying log+%28a%2C+%28bc%29%29+=+log+%28a%2C+%28b%29%29+%2B+log+%28a%2C+%28c%29%29
highlight%28log%283%2C+%289x%29%29%29 = 2 + 7 = 9 ---- Substituting 2 for log+%283%2C+%289%29%29 and 7 (GIVEN) for log+%283%2C+%28x%29%29