SOLUTION: Express as a single logarithm. loga 7 + loga 12

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Express as a single logarithm. loga 7 + loga 12       Log On


   



Question 313610: Express as a single logarithm.
loga 7 + loga 12

Found 2 solutions by rapaljer, Earlsdon:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
log+%28a%2C7%29%2Blog%28a%2C12%29
log+%28a%2C7%2A12%29
log+%28a%2C84%29


Please see my own website for all the FREE resources that I have there, including my OWN explanation of logarithms. To see my website, click on my tutor name "Rapaljer" anywhere in algebra.com. On my information page, click on the link to my website. Look for the link on my Homepage "Basic, Intermediate, and College Algebra: One Step at a Time." Choose "College Algebra", then "Chapter 4 (Logarithms)". This is my OWN non-traditional explanation, complete with examples, exercises, and ALL of the answers, that my own students found much easier to understand than the regular textbooks. See also my "Math in Living Color" pages that go with this section. In these pages, I explain the solutions to many of the exercises IN LIVING COLOR!!

See also the vidoes, made from my own classes a few years ago before I retired. I actually taught the entire chapter of LOGARITHMS on two 2 hour videos. These videos are now available FREE on my website. From my Homepage, look for the link "Rapalje Vidoes in Living Color".

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Express as a single logarithm:
Log%5Ba%5D%287%29%2BLog%5Ba%5D%2812%29+=+Log%5Ba%5D%287%2A12%29=Log%5Ba%5D%2884%29This is an application of "the product rule" for logarithms which states:
Log%5Bb%5D%28M%29%2BLog%5Bb%5D%28N%29+=+Log%5Bb%5D%28M%2AN%29