SOLUTION: how do you solve log base 5 (2x-7)=3?

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Question 306060: how do you solve
log base 5 (2x-7)=3?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
Log%5B5%5D%282x-7%29+=+3 Rewrite this in exponential form:Log%5Bb%5D%28x%29+=+y converts to b%5Ey+=+x, so...
Log%5B5%5D%282x-7%29+=+3--->5%5E3+=+2x-7 Substitute 5%5E3+=+125
125+=+2x-7 Add 7 to both sides.
132+=+2x Divide both sides by 2.
highlight%28x+=+66%29