SOLUTION: Pleaseee!!! And Thank you! " Expand the log: Log -no base- 7(3x-2)^2 "

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Pleaseee!!! And Thank you! " Expand the log: Log -no base- 7(3x-2)^2 "      Log On


   

Question 304777: Pleaseee!!! And Thank you! " Expand the log: Log -no base- 7(3x-2)^2 "
Found 2 solutions by london maths tutor, Alan3354:
Answer by london maths tutor(243) About Me  (Show Source):
You can put this solution on YOUR website!
log [7(3x-2)^2]
= 2 log [7(3x-2)]
= 2 log (21x - 14)
= %282+log%2821x%29%29+%2F+%282+log%2814%29%29
= %282+log%2821%29+%2B+2+log%28x%29%29+%2F+%282+log%2814%29%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
No base means it's base 10, or common logs
log%287%2A%283x-2%29%5E2%29
= log%287%29+%2B+2%2Alog%283x-2%29
No further expansion is possible.
The other tutor subtracted logs for subtraction, that's incorrect.