SOLUTION: solve for x lg(x-1)=ln(e^2-1)

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Question 301929: solve for x
lg(x-1)=ln(e^2-1)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assume the problem is
log(x-1) = ln(e^2-1)
:
find ln(e^2-1) on a calc
log(x-1) = 1.854585
:
find the antilog of both sides
x - 1 = 71.5462
x = 71.5462 + 1
x = 72.5462